21. Number is Armstonrg or not

       Armstorng no : If the sum of the digits of the cube of number is equal to original number then it is armstorng number .

      ex : take number n = 153;

          if  3*3*3 + 5*5*5 + 1*1*1 = 153 (i.e. same  number ,n )

          then, the number is Armstorng number.


 int n,r;
    int sum=0;
    Scanner sc = new Scanner(System.in);
    n=sc.nextInt();
     int store = n // to store the number ;
    while(n>0)
    {
        r=n%10;
        sum=sum+r*r*r;  //sum of the cuber of the number
        n=n/10;
    }
    System.out.println(sum);
    if (sum==store)
    {
        System.out.println(store +" is Armstrong no");
    }
    else
        System.out.println(store + " is not Armstrong no");
}

23564

440

23564 is not Armstrong no


Process finished with exit code 0

          

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